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How can we find the image name using PHP code?

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Vinh Jacker
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1 min read

If you want to retrieve the file name of an image using PHP, you can do so using various methods depending on the context:

If you have the image path:

If you have the path to the image, you can use PHP's basename() function to extract the file name:

phpCopy code$imagePath = 'path/to/your/image.jpg';
$imageName = basename($imagePath);
echo $imageName; // This will output: image.jpg

If you have an uploaded file:

When dealing with uploaded files, say from an HTML form, you can access the file name through the $_FILES array:

phpCopy codeif ($_FILES['file_input_name']['error'] === UPLOAD_ERR_OK) {
    $imageName = $_FILES['file_input_name']['name'];
    echo $imageName; // This will output the uploaded file name
}

If you have an image URL:

If you're working with an image URL, you can use pathinfo() to extract the file name:

phpCopy code$imageUrl = 'https://example.com/path/to/your/image.jpg';
$imageFileName = pathinfo($imageUrl, PATHINFO_BASENAME);
echo $imageFileName; // This will output: image.jpg

These methods allow you to retrieve the file name from different contexts based on the information available to you within your PHP code. Adjust the code based on your specific use case and how you're handling the image data.

image namePHP